What is the integral from 1 to 8 of 2/t ?

The integral from 1 to 8 of 2/t is 6ln(2)

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integral from 1 to 8 of 2/t

\int_{1}^{8} \frac{2}{t} d t

6 ln (2)

Decimal Notation

4.15888 \dots

Solution steps

\int_{1}^{8} \frac{2}{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{8} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= 2 [ln ∣ t ∣]_{1}^{8}

Compute the boundaries:

3 ln (2)

= 2 \cdot 3 ln (2)

Simplify

= 6 ln (2)

\int_{0}^{3} f (3 x) d x

\int_{0}^{1} b (a^{4 k - 1})

\int_{0}^{2} 2 e^{x^{2} - 3 x} d x

\int_{0}^{4} x^{2} \cdot \frac{x}{8} d x

\int_{0}^{4} 2 π x (2 x) d x

What is the integral from 1 to 8 of 2/t ?
The integral from 1 to 8 of 2/t is 6ln(2)