What is the integral from 1 to 7 of 4/x-4/(x^2) ?

The integral from 1 to 7 of 4/x-4/(x^2) is 4ln(7)-24/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 7 of 4/x-4/(x^2)

\int_{1}^{7} \frac{4}{x} - \frac{4}{x ^{2}} d x

4 ln (7) - \frac{24}{7}

Decimal Notation

4.35506 \dots

Solution steps

\int_{1}^{7} \frac{4}{x} - \frac{4}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{7} \frac{4}{x} d x - \int_{1}^{7} \frac{4}{x ^{2}} d x

\int_{1}^{7} \frac{4}{x} d x = 4 ln (7)

\int_{1}^{7} \frac{4}{x ^{2}} d x = \frac{24}{7}

= 4 ln (7) - \frac{24}{7}

\int_{0}^{20} π (x)^{2} d x

\int_{2}^{0} x^{4} - 2 x^{3} d x

\int_{- 2}^{2} 5 x d x

\int_{- 2}^{4} x^{2} + 5 x - 6 d x

\int_{a}^{9 a} \frac{1}{x} d x

What is the integral from 1 to 7 of 4/x-4/(x^2) ?
The integral from 1 to 7 of 4/x-4/(x^2) is 4ln(7)-24/7