What is the derivative of arctan(4x) ?

The derivative of arctan(4x) is 4/(16x^2+1)

What is the first derivative of arctan(4x) ?

The first derivative of arctan(4x) is 4/(16x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arctan (4 x)

\frac{4}{16 x ^{2} + 1}

Solution steps

\frac{d}{d x} (arctan (4 x))

Apply the chain rule:

\frac{1}{( 4 x ) ^{2} + 1} \frac{d}{d x} (4 x)

= \frac{1}{( 4 x ) ^{2} + 1} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= \frac{1}{( 4 x ) ^{2} + 1} \cdot 4

Simplify

\frac{1}{( 4 x ) ^{2} + 1} \cdot 4 : \frac{4}{16 x ^{2} + 1}

= \frac{4}{16 x ^{2} + 1}

\frac{d}{d x} (e^{x} + sin (x))

\int \frac{u}{u} d u

\frac{d y}{d x} + 4 y = 9

\frac{d}{d x} (\frac{x - 2}{9 x ^{2} e ^{x}})

\frac{\partial}{\partial x} (8 ln (\frac{3 x y}{5 z}))

What is the derivative of arctan(4x) ?
The derivative of arctan(4x) is 4/(16x^2+1)
What is the first derivative of arctan(4x) ?
The first derivative of arctan(4x) is 4/(16x^2+1)