What is the integral from 0 to 5 of 5e^x ?

The integral from 0 to 5 of 5e^x is 5(e^5-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of 5e^x

\int_{0}^{5} 5 e^{x} d x

5 (e^{5} - 1)

Decimal Notation

737.06579 \dots

Solution steps

\int_{0}^{5} 5 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{5} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 5 [e^{x}]_{0}^{5}

Compute the boundaries:

e^{5} - 1

= 5 (e^{5} - 1)

\int_{1}^{2} (x^{2} - 5 x) d x

\int_{0}^{a} 6 e^{x} d x

\int_{0}^{\frac{π}{3}} cos (x) - \frac{1}{2} d x

\int_{- 1}^{3} 4 - (x - 1)^{2} d x

\int_{0}^{1} (x arcsin (x^{2})) d x

What is the integral from 0 to 5 of 5e^x ?
The integral from 0 to 5 of 5e^x is 5(e^5-1)