What is the limit as x approaches 1 of sqrt(x^2+1) ?

The limit as x approaches 1 of sqrt(x^2+1) is square root of 2

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limit as x approaches 1 of sqrt(x^2+1)

x \to 1 lim (x^{2} + 1)

2

Decimal Notation

1.41421 \dots

Solution steps

x \to 1 lim (x^{2} + 1)

Plug in the value

x = 1

= 1^{2} + 1

Simplify

= 2

\int 1 + x d x

(3 x + 5)^{4} x

\int t e^{- 2} d t

y = - 4 x^{7} - 1

\int (cos (x) - sin (x)) d x

What is the limit as x approaches 1 of sqrt(x^2+1) ?
The limit as x approaches 1 of sqrt(x^2+1) is square root of 2