What is the integral from 0 to 1 of (x) ?

The integral from 0 to 1 of (x) is 1/2

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integral from 0 to 1 of (x)

\int_{0}^{1} (x) d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int - \frac{3 ( x + a )}{x ^{2} + a ^{2}} d x

\int cot^{6} (2 x) d x

\frac{d y}{d x}, y = (arctan (9 x))^{2}

\int_{0}^{\infty} \frac{1}{x ^{2} + 9} d x

x \to - 5 lim (\frac{1}{x ^{2} - 25})

What is the integral from 0 to 1 of (x) ?
The integral from 0 to 1 of (x) is 1/2