What is the derivative of e^{2sin(3v)} ?

The derivative of e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)

What is the first derivative of e^{2sin(3v)} ?

The first derivative of e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)

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derivative of

e^{2 s i n (3 v)}

e^{2 s i n (3 v)} \cdot 6 cos (3 v)

Solution steps

\frac{d}{d v} (e^{2 s i n (3 v)})

Apply the chain rule:

e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

= e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

\frac{d}{d v} (2 sin (3 v)) = 6 cos (3 v)

= e^{2 s i n (3 v)} \cdot 6 cos (3 v)

2 - 2 x

f (x) = \frac{x - ln ( 1 + x )}{x ^{2}}

\int 63 sec^{4} (θ) tan^{6} (θ) d θ

\frac{d}{d x} (x y + ln (\frac{x}{y}))

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = \frac{25}{3}

What is the derivative of e^{2sin(3v)} ?
The derivative of e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)
What is the first derivative of e^{2sin(3v)} ?
The first derivative of e^{2sin(3v)} is e^{2sin(3v)}*6cos(3v)