What is the integral of integral of-1/x ?

The integral of integral of-1/x is x(-ln(x)+C)+x+C

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integral of integral of-1/x

\int \int - \frac{1}{x} d x d x

x (- ln (x) + C) + x + C

Solution steps

\int \int - \frac{1}{x} d x d x

\int - \frac{1}{x} d x = - ln (x) + C

= \int (- ln (x) + C) d x

\int (- ln (x) + C) d x = x (- ln (x) + C) + x + C

= x (- ln (x) + C) + x + C

\int_{- 2}^{2} \int_{0}^{4 - x^{2}} x^{2} + y^{2} d y d x

\int_{0}^{π} \int_{0}^{\frac{π}{2}} cos (x + 2 y) d y d x

\int \int e^{- (x^{2} + y^{2})} d A

\int \int ln (x) d x d x

\int \int e^{2 x} d x d x

What is the integral of integral of-1/x ?
The integral of integral of-1/x is x(-ln(x)+C)+x+C