What is (\partial)/(\partial x)(x^2+ln(y)) ?

The answer to (\partial)/(\partial x)(x^2+ln(y)) is 2x

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(\partial)/(\partial x)(x^2+ln(y))

\frac{\partial}{\partial x} (x^{2} + ln (y))

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + ln (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (ln (y))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (ln (y)) = 0

= 2 x + 0

Simplify

= 2 x

\frac{\partial}{\partial s} (\frac{r + s}{t})

sin (9 ln (x))

y^{^{'}} = 3 y - 1

\frac{3 s + 3}{( s + 4 ) ^{2}}

\int \frac{1}{441 - x ^{2}} d x

What is (\partial)/(\partial x)(x^2+ln(y)) ?
The answer to (\partial)/(\partial x)(x^2+ln(y)) is 2x