What is the derivative of cos(x+x) ?

The derivative of cos(x+x) is -sin(x)+1

What is the first derivative of cos(x+x) ?

The first derivative of cos(x+x) is -sin(x)+1

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\frac{d}{d x} (cos (x) + x)

- sin (x) + 1

Solution steps

\frac{d}{d x} (cos (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (x)) + \frac{d x}{d x}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d x}{d x} = 1

= - sin (x) + 1

\frac{d}{d x} (3 x^{2} - 12 x)

\int ln (12 x) d x

2 x y y^{^{'}} = 4 x^{2} + 3 y^{2}

\int_{0}^{1} \int_{- 1}^{∣ x ∣^{- 1}} (x + y)^{2} d y d x

\int 2 x e^{x^{2} + 3} d x

What is the derivative of cos(x+x) ?
The derivative of cos(x+x) is -sin(x)+1
What is the first derivative of cos(x+x) ?
The first derivative of cos(x+x) is -sin(x)+1