What is the integral of integral of 1/(x+y) ?

The integral of integral of 1/(x+y) is Cy+xln(x+y)+yln(x+y)-x-y+C

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integral of integral of 1/(x+y)

\int \int \frac{1}{x + y} d x d y

C y + x ln (x + y) + y ln (x + y) - x - y + C

Solution steps

\int \int \frac{1}{x + y} d x d y

\int \frac{1}{x + y} d x = ln (y + x) + C

= \int (ln (y + x) + C) d y

\int (ln (y + x) + C) d y = C y + x ln (x + y) + y ln (x + y) - x - y + C

= C y + x ln (x + y) + y ln (x + y) - x - y + C

\int \int \int 0 d x d y d z

\int \int 1 - x^{2} d x d x

\int \int (x + y + 1) d x d y

\int \int 2 x y d x d y

\int \int x^{2} + y^{2}

What is the integral of integral of 1/(x+y) ?
The integral of integral of 1/(x+y) is Cy+xln(x+y)+yln(x+y)-x-y+C