What is (\partial)/(\partial x)(4+cos(0.4x-t)) ?

The answer to (\partial)/(\partial x)(4+cos(0.4x-t)) is -0.4sin(0.4x-t)

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(\partial)/(\partial x)(4+cos(0.4x-t))

\frac{\partial}{\partial x} (4 + cos (0.4 x - t))

- 0.4 sin (0.4 x - t)

Solution steps

\frac{\partial}{\partial x} (4 + cos (0.4 x - t))

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4) + \frac{\partial}{\partial x} (cos (0.4 x - t))

\frac{\partial}{\partial x} (4) = 0

\frac{\partial}{\partial x} (cos (0.4 x - t)) = - sin (0.4 x - t) \cdot 0.4

= 0 - sin (0.4 x - t) \cdot 0.4

Simplify

= - 0.4 sin (0.4 x - t)

(e^{x})^{3}

(4 x^{3} + 3 x^{2} + 3 y - 1) d x + (3 x + 2 y + 1) d y = 0

x \to \infty lim (\frac{5 e ^{- 3 x} + 2}{e ^{- 5 x} + 4})

\frac{d}{d x} (2^{2 - x^{4}})

\int \frac{e ^{\frac{x ^{2}}{2}}}{x ^{2}} d x

What is (\partial)/(\partial x)(4+cos(0.4x-t)) ?
The answer to (\partial)/(\partial x)(4+cos(0.4x-t)) is -0.4sin(0.4x-t)