What is the derivative of xln(x-1) ?

The derivative of xln(x-1) is ln(x)+1

What is the first derivative of xln(x-1) ?

The first derivative of xln(x-1) is ln(x)+1

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\frac{d}{d x} (x ln (x) - 1)

ln (x) + 1

Solution steps

\frac{d}{d x} (x ln (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x ln (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (x ln (x)) = ln (x) + 1

\frac{d}{d x} (1) = 0

= ln (x) + 1 - 0

Simplify

= ln (x) + 1

\int t^{2} e^{- 2 t} d t

\int \frac{( e ^{2 x} - 1 )}{( e ^{x} + e ^{- x} )} d x

\frac{d}{d x} (\frac{2 x}{3 x ^{2} - 12})

(x^{3} + 4) (3 x^{2} - 4 x + 2)

3 t^{2} + 15 t + 19

What is the derivative of xln(x-1) ?
The derivative of xln(x-1) is ln(x)+1
What is the first derivative of xln(x-1) ?
The first derivative of xln(x-1) is ln(x)+1