What is the integral from 1 to infinity of sqrt(x) ?

The integral from 1 to infinity of sqrt(x) is diverges

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integral from 1 to infinity of sqrt(x)

\int_{1}^{\infty} x d x

diverges

Solution steps

\int_{1}^{\infty} x d x

Compute the indefinite integral:

\int x d x = \frac{2}{3} x^{\frac{3}{2}} + C

Compute the boundaries:

\int_{1}^{\infty} x d x =

diverges

= diverges

\frac{\partial}{\partial x} (1 + ln (y) + \frac{x}{y})

\frac{d y}{d x} = \frac{y}{x} + 3 x + 7

3 x^{4} - 12 x^{3}

\frac{d}{d x} (sin^{5} (\frac{x}{3}))

\int \frac{1}{x ^{2} 8 - x ^{2}} d x

What is the integral from 1 to infinity of sqrt(x) ?
The integral from 1 to infinity of sqrt(x) is diverges