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Popular >

integral from 1 to 2 of integral from-v to v of e^{u/v}*1/2

Solution

\int_{1}^{2} \int_{- v}^{v} e^{\frac{u}{v}} \cdot \frac{1}{2} d u d v

Solution

\frac{3 ( e ^{2} - 1 )}{4 e}

+1

Decimal Notation

1.76280 \dots

Solution steps

\int_{1}^{2} \int_{- v}^{v} e^{\frac{u}{v}} \frac{1}{2} d u d v

\int_{- v}^{v} e^{\frac{u}{v}} \frac{1}{2} d u = \frac{( e ^{2} - 1 ) v}{2 e}

= \int_{1}^{2} (\frac{( e ^{2} - 1 ) v}{2 e}) d v

\int_{1}^{2} (\frac{( e ^{2} - 1 ) v}{2 e}) d v = \frac{3 ( e ^{2} - 1 )}{4 e}

= \frac{3 ( e ^{2} - 1 )}{4 e}

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of integral from-v to v of e^{u/v}*1/2 ?
The integral from 1 to 2 of integral from-v to v of e^{u/v}*1/2 is (3(e^2-1))/(4e)