What is the derivative of 0.5sin(2x) ?

The derivative of 0.5sin(2x) is cos(2x)

What is the first derivative of 0.5sin(2x) ?

The first derivative of 0.5sin(2x) is cos(2x)

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\frac{d}{d x} (0.5 sin (2 x))

cos (2 x)

Solution steps

\frac{d}{d x} (0.5 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.5 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 0.5 cos (2 x) \cdot 2

Simplify

= cos (2 x)

x^{2} - 4 x + 3, - x^{2} + 2 x + 3

sin (a x^{2})

\int (x^{2} - 4) d x

\frac{d}{d x} ((x^{2} - 3)^{2})

y = \frac{1}{20 x ^{2}}, x = y, y = \frac{x}{16}

What is the derivative of 0.5sin(2x) ?
The derivative of 0.5sin(2x) is cos(2x)
What is the first derivative of 0.5sin(2x) ?
The first derivative of 0.5sin(2x) is cos(2x)