What is the integral of integral of (3x-3y) ?

The integral of integral of (3x-3y) is Cy+(3x^2)/2 y-(3xy^2)/2+C

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integral of integral of (3x-3y)

\int \int (3 x - 3 y) d x d y

C y + \frac{3 x ^{2}}{2} y - \frac{3 x y ^{2}}{2} + C

Solution steps

\int \int (3 x - 3 y) d x d y

\int (3 x - 3 y) d x = - 3 y x + \frac{3 x ^{2}}{2} + C

= \int (- 3 y x + \frac{3 x ^{2}}{2} + C) d y

\int (- 3 y x + \frac{3 x ^{2}}{2} + C) d y = C y + \frac{3 x ^{2}}{2} y - \frac{3 x y ^{2}}{2} + C

= C y + \frac{3 x ^{2}}{2} y - \frac{3 x y ^{2}}{2} + C

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What is the integral of integral of (3x-3y) ?
The integral of integral of (3x-3y) is Cy+(3x^2)/2 y-(3xy^2)/2+C