What is the solution for (yx-y)dy-(y+1)dx=0 ?

The solution for (yx-y)dy-(y+1)dx=0 is y=-\W(-(c_{1})/(x-1))-1

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(yx-y)dy-(y+1)dx=0

(y x - y) d y - (y + 1) d x = 0

y = - W (- \frac{c _{1}}{x - 1}) - 1

Solution steps

(y x - y) d y - (y + 1) d x = 0

Solve separable ODE:

y = - W (- \frac{c _{1}}{x - 1}) - 1

y = - W (- \frac{c _{1}}{x - 1}) - 1

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What is the solution for (yx-y)dy-(y+1)dx=0 ?
The solution for (yx-y)dy-(y+1)dx=0 is y=-\W(-(c_{1})/(x-1))-1