What is the integral of x/(32)+1/8 ?

The integral of x/(32)+1/8 is (x^2)/(64)+1/8 x+C

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integral of x/(32)+1/8

\int \frac{x}{32} + \frac{1}{8} d x

\frac{x ^{2}}{64} + \frac{1}{8} x + C

Solution steps

\int \frac{x}{32} + \frac{1}{8} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{32} d x + \int \frac{1}{8} d x

\int \frac{x}{32} d x = \frac{x ^{2}}{64}

\int \frac{1}{8} d x = \frac{1}{8} x

= \frac{x ^{2}}{64} + \frac{1}{8} x

Add a constant to the solution

= \frac{x ^{2}}{64} + \frac{1}{8} x + C

\int x + e^{x} d x

x \to \infty lim ((1 + sin (6 x))^{\frac{1}{3 x}})

x \to 1 lim (x \cdot ln (x))

t \to \infty lim (\frac{1 - e ^{- 2 t}}{t})

\int \frac{1}{x ^{2} - 2 x + 5} d x

What is the integral of x/(32)+1/8 ?
The integral of x/(32)+1/8 is (x^2)/(64)+1/8 x+C