What is the limit as x approaches infinity of 52.2+(41.9*e^{(-0.055*x)}) ?

The limit as x approaches infinity of 52.2+(41.9*e^{(-0.055*x)}) is 52.2

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limit as x approaches infinity of 52.2+(41.9e^{(-0.055x)})

x \to \infty lim (52.2 + (41.9 \cdot e^{(- 0.055 \cdot x)}))

52.2

Solution steps

x \to \infty lim (52.2 + 41.9 e^{- 0.055 x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (52.2) + x \to \infty lim (41.9 e^{- 0.055 x})

x \to \infty lim (52.2) = 52.2

x \to \infty lim (41.9 e^{- 0.055 x}) = 0

= 52.2 + 0

Simplify

= 52.2

\frac{d}{d x} (ln (x^{2} + y))

\int \frac{1}{3 cos ( x ) + 4 sin ( x )} d x

x \to - \infty lim (0 x)

\int 2 x + 22 d x

f (x) = ln (x) cos (x)

What is the limit as x approaches infinity of 52.2+(41.9*e^{(-0.055*x)}) ?
The limit as x approaches infinity of 52.2+(41.9*e^{(-0.055*x)}) is 52.2