What is the integral of integral of (6x^2+4xy^3) ?

The integral of integral of (6x^2+4xy^3) is Cy+2x^3y+(x^2y^4)/2+C

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integral of integral of (6x^2+4xy^3)

\int \int (6 x^{2} + 4 x y^{3}) d x d y

C y + 2 x^{3} y + \frac{x ^{2} y ^{4}}{2} + C

Solution steps

\int \int (6 x^{2} + 4 x y^{3}) d x d y

\int (6 x^{2} + 4 x y^{3}) d x = 2 x^{3} + 2 y^{3} x^{2} + C

= \int (2 x^{3} + 2 y^{3} x^{2} + C) d y

\int (2 x^{3} + 2 y^{3} x^{2} + C) d y = C y + 2 x^{3} y + \frac{x ^{2} y ^{4}}{2} + C

= C y + 2 x^{3} y + \frac{x ^{2} y ^{4}}{2} + C

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What is the integral of integral of (6x^2+4xy^3) ?
The integral of integral of (6x^2+4xy^3) is Cy+2x^3y+(x^2y^4)/2+C