What is the solution for x^2(dy)/(dx)=1-x^2+y^2-x^2y^2 ?

The solution for x^2(dy)/(dx)=1-x^2+y^2-x^2y^2 is y=tan(-x-1/x+c_{1})

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x^2(dy)/(dx)=1-x^2+y^2-x^2y^2

x^{2} \frac{d y}{d x} = 1 - x^{2} + y^{2} - x^{2} y^{2}

y = tan (- x - \frac{1}{x} + c_{1})

Solution steps

x^{2} \frac{d y}{d x} = 1 - x^{2} + y^{2} - x^{2} y^{2}

Solve separable ODE:

y = tan (- x - \frac{1}{x} + c_{1})

y = tan (- x - \frac{1}{x} + c_{1})

\int (x - a)^{2} d x

\int \frac{x ^{2} + 1}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\frac{x - 13}{x - 13}

\int_{- 5}^{5} \frac{1}{2} (25 - x^{2}) d x

(6 x + 1) y^{2} \frac{d y}{d x} + 4 x^{2} + 2 y^{3} = 0

What is the solution for x^2(dy)/(dx)=1-x^2+y^2-x^2y^2 ?
The solution for x^2(dy)/(dx)=1-x^2+y^2-x^2y^2 is y=tan(-x-1/x+c_{1})