What is the limit as x approaches 0 of (1+x)^{ln(x)} ?

The limit as x approaches 0 of (1+x)^{ln(x)} is Does not exist

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limit as x approaches 0 of (1+x)^{ln(x)}

x \to 0 lim ((1 + x)^{l n (x)})

Does not exist

Solution steps

x \to 0 lim ((1 + x)^{l n (x)})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + x)^{l n (x)}) = 1

x \to 0 - lim ((1 + x)^{l n (x)}) =

Does not exist

= Does not exist

x \to \infty lim (\frac{x ^{2}}{x e ^{- x}})

x \to 0 + lim (\frac{e ^{x} - 1}{x ^{2}})

x \to 0 lim (\frac{sin ( 2 x )}{x} + 1)

x \to 0 + lim (x sin (\frac{1}{5 x}))

What is the limit as x approaches 0 of (1+x)^{ln(x)} ?
The limit as x approaches 0 of (1+x)^{ln(x)} is Does not exist