What is the solution for x^2y^{''}+3xy^'-15y=0 ?

The solution for x^2y^{''}+3xy^'-15y=0 is y=c_{1}x^3+(c_{2})/(x^5)

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x^2y^{''}+3xy^'-15y=0

x^{2} y^{^{''}} + 3 x y^{^{'}} - 15 y = 0

y = c_{1} x^{3} + \frac{c _{2}}{x ^{5}}

Solution steps

x^{2} y^{''} (x) + 3 x y^{'} (x) - 15 y = 0

Solve linear ODE:

y = c_{1} x^{3} + \frac{c _{2}}{x ^{5}}

y = c_{1} x^{3} + \frac{c _{2}}{x ^{5}}

\frac{6}{s ^{2} + 5 s + 6}

x \to 4 lim (\frac{x ^{2} + x}{x + 1})

y = 17 - x^{2}, x = 0, y = 0

\int \frac{( x ^{2} - 1 )}{( x ^{2} + 1 )} d x

\frac{\partial}{\partial x} (2 x e^{y})

What is the solution for x^2y^{''}+3xy^'-15y=0 ?
The solution for x^2y^{''}+3xy^'-15y=0 is y=c_{1}x^3+(c_{2})/(x^5)