What is the limit as x approaches-7 of (4x-1)/(x+7) ?

The limit as x approaches-7 of (4x-1)/(x+7) is diverges

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limit as x approaches-7 of (4x-1)/(x+7)

x \to - 7 lim (\frac{4 x - 1}{x + 7})

diverges

Solution steps

x \to - 7 lim (\frac{4 x - 1}{x + 7})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 7 + lim (\frac{4 x - 1}{x + 7}) = - \infty

x \to - 7 - lim (\frac{4 x - 1}{x + 7}) = \infty

= diverges

x \to 8 + lim (\frac{x}{x - 8})

h \to 0 lim (f (x, h) (x + h))

x \to 0 lim ((4 x)^{x})

x \to 0 lim ((1 + x^{2})^{\frac{3}{x}})

x \to - \infty lim (e^{x} + 3)

What is the limit as x approaches-7 of (4x-1)/(x+7) ?
The limit as x approaches-7 of (4x-1)/(x+7) is diverges