What is the limit as x approaches 0 of (ln(x+1))^x ?

The limit as x approaches 0 of (ln(x+1))^x is Does not exist

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limit as x approaches 0 of (ln(x+1))^x

x \to 0 lim ((ln (x + 1))^{x})

Does not exist

Solution steps

x \to 0 lim ((ln (x + 1))^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((ln (x + 1))^{x}) = 1

x \to 0 - lim ((ln (x + 1))^{x}) =

Does not exist

= Does not exist

x \to a lim (3 x^{2} + 4 x - 5)

x \to - \frac{π}{2} + lim (cos (x))

x \to \infty lim (\frac{10 - 6 x ^{2}}{5 + 3 e ^{x}})

x \to - 2 - lim (\frac{x - 2}{x ^{2} - 4})

x \to - \frac{a}{2} lim (4 x^{2} - 3 x + 1)

What is the limit as x approaches 0 of (ln(x+1))^x ?
The limit as x approaches 0 of (ln(x+1))^x is Does not exist