What is the limit as x approaches-3+of (x+1)/(x^2-9) ?

The limit as x approaches-3+of (x+1)/(x^2-9) is infinity

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limit as x approaches-3+of (x+1)/(x^2-9)

x \to - 3 + lim (\frac{x + 1}{x ^{2} - 9})

\infty

Solution steps

x \to - 3 + lim (\frac{x + 1}{x ^{2} - 9})

\frac{x + 1}{x ^{2} - 9} = (x + 1) \frac{1}{x ^{2} - 9}

= x \to - 3 + lim ((x + 1) \frac{1}{x ^{2} - 9})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 3 + lim (x + 1) \cdot x \to - 3 + lim (\frac{1}{x ^{2} - 9})

x \to - 3 + lim (x + 1) = - 2

x \to - 3 + lim (\frac{1}{x ^{2} - 9}) = - \infty

= (- 2) (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

x \to 4 lim (\frac{x - 4}{4 - x})

x \to 0 lim (\frac{7 ^{x} - 1}{5 x})

x \to \frac{π}{4} lim (\frac{4 x}{tan ( x )})

x \to 2 lim (\frac{7}{x - 1})

x \to 3 - lim ((x) + (4 - x))

What is the limit as x approaches-3+of (x+1)/(x^2-9) ?
The limit as x approaches-3+of (x+1)/(x^2-9) is infinity