What is the limit as x approaches 1 of ln(x)ln(x-1) ?

The limit as x approaches 1 of ln(x)ln(x-1) is Does not exist

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limit as x approaches 1 of ln(x)ln(x-1)

x \to 1 lim (ln (x) ln (x - 1))

Does not exist

Solution steps

x \to 1 lim (ln (x) ln (x - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (ln (x) ln (x - 1)) = 0

x \to 1 - lim (ln (x) ln (x - 1)) =

Does not exist

= Does not exist

x \to 0 lim (\frac{5 x}{3 sin ( x ) cos ( x )})

x \to - \frac{π}{2} lim (cos (x))

x \to 2 lim (x^{3} - 2 x^{2} - 2)

x \to 0 lim (\frac{x}{x + sin ( 2 x )})

x \to 1 lim ((x - 1)^{x})

What is the limit as x approaches 1 of ln(x)ln(x-1) ?
The limit as x approaches 1 of ln(x)ln(x-1) is Does not exist