What is the limit as x approaches 0 of ln(x^x) ?

The limit as x approaches 0 of ln(x^x) is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ln(x^x)

x \to 0 lim (ln (x^{x}))

Does not exist

Solution steps

x \to 0 lim (ln (x^{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (x^{x})) = 0

x \to 0 - lim (ln (x^{x})) =

Does not exist

= Does not exist

x \to - \infty lim (x, 4)

x \to \frac{π}{2} lim (2 x cos (x))

x \to 0 + lim (\frac{ln ( x )}{e ^{x}})

x \to 2 lim (\frac{x}{6 - 3 x})

x \to 0 + lim (x^{0.0001} ln (x))

What is the limit as x approaches 0 of ln(x^x) ?
The limit as x approaches 0 of ln(x^x) is Does not exist