What is the limit as x approaches-1 of 2x^2+x+4 ?

The limit as x approaches-1 of 2x^2+x+4 is 5

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limit as x approaches-1 of 2x^2+x+4

x \to - 1 lim (2 x^{2} + x + 4)

5

Solution steps

x \to - 1 lim (2 x^{2} + x + 4)

Plug in the value

x = - 1

= 2 (- 1)^{2} - 1 + 4

Simplify

2 (- 1)^{2} - 1 + 4 : 5

= 5

x \to 3 lim (ln (\frac{1}{x - 3}))

x \to - 4 lim (2 x^{2})

x \to 4 lim (3 x^{2} + x - 2)

x \to 0 lim (\frac{3 sin ( 4 x )}{x})

x \to 0 + lim (x ln^{2} (x))

What is the limit as x approaches-1 of 2x^2+x+4 ?
The limit as x approaches-1 of 2x^2+x+4 is 5