What is the derivative of sin^3(3x) ?

The derivative of sin^3(3x) is 9sin^2(3x)cos(3x)

What is the first derivative of sin^3(3x) ?

The first derivative of sin^3(3x) is 9sin^2(3x)cos(3x)

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derivative of

sin^{3} (3 x)

9 sin^{2} (3 x) cos (3 x)

Solution steps

\frac{d}{d x} (sin^{3} (3 x))

Apply the chain rule:

3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

= 3 (sin (3 x))^{2} \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 3 (sin (3 x))^{2} cos (3 x) \cdot 3

Simplify

= 9 sin^{2} (3 x) cos (3 x)

\frac{\partial}{\partial y} (- 2 cos (y))

\frac{\partial}{\partial x} (x^{4} - y^{2})

\frac{d}{d x} (\frac{x ^{2} + 1}{x ^{2} - 3})

f (x) = cos^{3} (x)

ln (\frac{1}{x})

What is the derivative of sin^3(3x) ?
The derivative of sin^3(3x) is 9sin^2(3x)cos(3x)
What is the first derivative of sin^3(3x) ?
The first derivative of sin^3(3x) is 9sin^2(3x)cos(3x)