What is the integral from 0 to 14 of 2pix(14x-x^2) ?

The integral from 0 to 14 of 2pix(14x-x^2) is (19208pi)/3

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integral from 0 to 14 of 2pix(14x-x^2)

\int_{0}^{14} 2 π x (14 x - x^{2}) d x

\frac{19208 π}{3}

Decimal Notation

20114.57056 \dots

Solution steps

\int_{0}^{14} 2 π x (14 x - x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int_{0}^{14} x (14 x - x^{2}) d x

Expand

x (14 x - x^{2}) : 14 x^{2} - x^{3}

= 2 π \cdot \int_{0}^{14} 14 x^{2} - x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 π (\int_{0}^{14} 14 x^{2} d x - \int_{0}^{14} x^{3} d x)

\int_{0}^{14} 14 x^{2} d x = \frac{38416}{3}

\int_{0}^{14} x^{3} d x = 9604

= 2 π (\frac{38416}{3} - 9604)

Simplify

2 π (\frac{38416}{3} - 9604) : \frac{19208 π}{3}

= \frac{19208 π}{3}

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What is the integral from 0 to 14 of 2pix(14x-x^2) ?
The integral from 0 to 14 of 2pix(14x-x^2) is (19208pi)/3