What is area |sqrt(x+4)-2|,|sqrt(16-x)|,0,16 ?

The answer to area |sqrt(x+4)-2|,|sqrt(16-x)|,0,16 is 24+(80sqrt(5)-168)/3

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area |sqrt(x+4)-2|,|sqrt(16-x)|,0,16

area

x + 4 - 2, 16 - x, 0, 16

24 + \frac{80 5 - 168}{3}

Decimal Notation

27.62847 \dots

Solution steps

Apply the area formula:

\int_{0}^{16} x + 4 - 2 - 16 - x d x

Solve

\int_{0}^{16} x + 4 - 2 - 16 - x d x : 24 + \frac{80 5 - 168}{3}

The area is:

= 24 + \frac{80 5 - 168}{3}

\int_{0}^{1} \frac{11}{4 y - 1} d y

n = 1 \sum \infty \frac{n}{n ^{2}}

\int_{0}^{1} ln (3 x) d x

\int \frac{2 x}{( 2 + 3 x ^{2} ) ^{3}} d x

\int_{0}^{4} \frac{1}{x ^{2} + 16} d x

What is area |sqrt(x+4)-2|,|sqrt(16-x)|,0,16 ?
The answer to area |sqrt(x+4)-2|,|sqrt(16-x)|,0,16 is 24+(80sqrt(5)-168)/3