What is the limit as x approaches 5 of (x^2-5)/(x-5) ?

The limit as x approaches 5 of (x^2-5)/(x-5) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of (x^2-5)/(x-5)

x \to 5 lim (\frac{x ^{2} - 5}{x - 5})

diverges

Solution steps

x \to 5 lim (\frac{x ^{2} - 5}{x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 5 + lim (\frac{x ^{2} - 5}{x - 5}) = \infty

x \to 5 - lim (\frac{x ^{2} - 5}{x - 5}) = - \infty

= diverges

x \to \infty lim (3, x)

x \to 0 lim (ln (1 + 2 x))

x \to 0 lim (\frac{x}{e ^{3 x} - 1})

x \to 3 + lim (\frac{3 - x}{∣ 3 - x ∣})

x \to 0 - lim (2^{\frac{1}{2}})

What is the limit as x approaches 5 of (x^2-5)/(x-5) ?
The limit as x approaches 5 of (x^2-5)/(x-5) is diverges