What is the limit as x approaches 1 of (ln(x))/(e^x) ?

The limit as x approaches 1 of (ln(x))/(e^x) is 0

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limit as x approaches 1 of (ln(x))/(e^x)

x \to 1 lim (\frac{ln ( x )}{e ^{x}})

0

Solution steps

x \to 1 lim (\frac{ln ( x )}{e ^{x}})

Plug in the value

x = 1

= \frac{ln ( 1 )}{e ^{1}}

Simplify

\frac{ln ( 1 )}{e ^{1}} : 0

= 0

x \to \infty lim (3 x^{2} + x)

x \to - \infty lim (- 3 x^{4})

x \to - 2 + lim (\frac{x}{x + 2})

x \to 0 lim (\frac{x}{ln ( 5 x + 1 )})

x \to 2 lim (\frac{x ^{3} - 2 x ^{2} - 6 x + 12}{x ^{2} + 3 x - 10})

What is the limit as x approaches 1 of (ln(x))/(e^x) ?
The limit as x approaches 1 of (ln(x))/(e^x) is 0