What is the limit as x approaches 0 of (e^{x-1})/x ?

The limit as x approaches 0 of (e^{x-1})/x is diverges

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limit as x approaches 0 of (e^{x-1})/x

x \to 0 lim (\frac{e ^{x - 1}}{x})

diverges

Solution steps

x \to 0 lim (\frac{e ^{x - 1}}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{e ^{x - 1}}{x}) = \infty

x \to 0 - lim (\frac{e ^{x - 1}}{x}) = - \infty

= diverges

x \to - 2 + lim (\frac{1}{4 - x ^{2}})

x \to \infty lim (\frac{2 x + 5}{x ^{2} - 7 x + 3})

x \to 0 + lim (\frac{x}{sin ( x )})

x \to 0 + lim (g (x) (x)^{c o t (x)})

x \to - \infty lim (3 x e^{x})

What is the limit as x approaches 0 of (e^{x-1})/x ?
The limit as x approaches 0 of (e^{x-1})/x is diverges