What is the solution for y^'=(x^2+y^2)/(xy) ?

The solution for y^'=(x^2+y^2)/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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y^'=(x^2+y^2)/(xy)

y^{^{'}} = \frac{x ^{2} + y ^{2}}{x y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{x ^{2} + y ^{2}}{x y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

\frac{\partial}{\partial x} (x + 3 y)

\int (3 x^{2} + 2 x) ln (x) d x

(x^{2} + y^{2} + 1) d x + x (x - 2 y) d y = 0

\frac{d}{d x} ((1 + sin (3 x))^{4})

\frac{d}{d x} ((3 cos (2 x) + sin (3 x) + 4)^{2})

What is the solution for y^'=(x^2+y^2)/(xy) ?
The solution for y^'=(x^2+y^2)/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}