What is the limit as x approaches infinity of (1-2/x)^{x/2-1} ?

The limit as x approaches infinity of (1-2/x)^{x/2-1} is 1/e

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limit as x approaches infinity of (1-2/x)^{x/2-1}

x \to \infty lim ((1 - \frac{2}{x})^{\frac{x}{2} - 1})

\frac{1}{e}

Decimal Notation

0.36787 \dots

Solution steps

x \to \infty lim ((1 - \frac{2}{x})^{\frac{x}{2} - 1})

Simplify

(1 - \frac{2}{x})^{\frac{x}{2} - 1} : (1 - \frac{2}{x})^{\frac{x}{2}} (1 - \frac{2}{x})^{- 1}

= x \to \infty lim ((1 - \frac{2}{x})^{\frac{x}{2}} (1 - \frac{2}{x})^{- 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim ((1 - \frac{2}{x})^{\frac{x}{2}}) \cdot x \to \infty lim ((1 - \frac{2}{x})^{- 1})

x \to \infty lim ((1 - \frac{2}{x})^{\frac{x}{2}}) = \frac{1}{e}

x \to \infty lim ((1 - \frac{2}{x})^{- 1}) = 1

= \frac{1}{e} \cdot 1

Simplify

= \frac{1}{e}

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x \to 2 lim (\frac{4 ln ( 2 x - 3 )}{2 e ^{2 x - 4} - 2})

x \to 0 lim (x^{2} sec^{2} (x))

x \to \infty lim (3 x e^{x})

What is the limit as x approaches infinity of (1-2/x)^{x/2-1} ?
The limit as x approaches infinity of (1-2/x)^{x/2-1} is 1/e