What is the limit as x approaches-infinity of 2^x-1 ?

The limit as x approaches-infinity of 2^x-1 is -1

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limit as x approaches-infinity of 2^x-1

x \to - \infty lim (2^{x} - 1)

- 1

Solution steps

x \to - \infty lim (2^{x} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (2^{x}) - x \to - \infty lim (1)

x \to - \infty lim (2^{x}) = 0

x \to - \infty lim (1) = 1

= 0 - 1

Simplify

= - 1

x \to 2 lim (e^{x^{2} - 2})

x \to 3 lim (\frac{5 x + 3}{x - 1})

x \to 0 lim (\frac{cos ( x )}{1})

x \to 0 lim (ln (1 + e^{- x}))

x \to - \infty lim (\frac{a x ^{2} + b x + c}{d - a x})

What is the limit as x approaches-infinity of 2^x-1 ?
The limit as x approaches-infinity of 2^x-1 is -1