What is the limit as x approaches-1 of (x^2+6)/(x+1) ?

The limit as x approaches-1 of (x^2+6)/(x+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of (x^2+6)/(x+1)

x \to - 1 lim (\frac{x ^{2} + 6}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x ^{2} + 6}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x ^{2} + 6}{x + 1}) = \infty

x \to - 1 - lim (\frac{x ^{2} + 6}{x + 1}) = - \infty

= diverges

x \to - \infty lim (x, - 1)

x \to 3 lim (3 x^{2})

x \to - \infty lim (\frac{6 x}{x + cos ( x )})

x \to 3 lim (x^{2} - 6 x + 4)

x \to 0 lim (\frac{5 x - tan ( 5 x )}{x ^{3}})

What is the limit as x approaches-1 of (x^2+6)/(x+1) ?
The limit as x approaches-1 of (x^2+6)/(x+1) is diverges