What is the derivative of y=4*5^x ?

The derivative of y=4*5^x is 4*5^xln(5)

What is the first derivative of y=4*5^x ?

The first derivative of y=4*5^x is 4*5^xln(5)

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derivative of

y = 4 \cdot 5^{x}

4 \cdot 5^{x} ln (5)

Solution steps

\frac{d}{d x} (4 \cdot 5^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (5^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4 \cdot 5^{x} ln (5)

\frac{d}{d x} (\frac{x ( x ^{2} - 1 )}{x ^{2} + 1})

x \to 0 lim (x^{2} (sin (\frac{1}{x})))

\int x^{2} 3 + 2 x - x^{2} d x

\frac{d}{d x} (4 e^{\frac{x}{2}} - 3 e^{- x})

\int_{0}^{\frac{π}{2}} x sin (8 x) d x

What is the derivative of y=4*5^x ?
The derivative of y=4*5^x is 4*5^xln(5)
What is the first derivative of y=4*5^x ?
The first derivative of y=4*5^x is 4*5^xln(5)