What is the limit as x approaches-1 of (7x+3)/(x+1) ?

The limit as x approaches-1 of (7x+3)/(x+1) is diverges

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limit as x approaches-1 of (7x+3)/(x+1)

x \to - 1 lim (\frac{7 x + 3}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{7 x + 3}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{7 x + 3}{x + 1}) = - \infty

x \to - 1 - lim (\frac{7 x + 3}{x + 1}) = \infty

= diverges

x \to c lim (5 x^{2} + b)

x \to 0 + lim (6 x ln (x))

x \to - 2 - lim (\frac{x ^{2} - x}{x + 2})

x \to 4 lim (\frac{x ^{3} - 8 x ^{2} + 18 x - 8}{x - 4})

x \to 0 - lim (\frac{1}{cos ( x )})

What is the limit as x approaches-1 of (7x+3)/(x+1) ?
The limit as x approaches-1 of (7x+3)/(x+1) is diverges