What is the limit as x approaches 0+of (e^x+10)^{5x} ?

The limit as x approaches 0+of (e^x+10)^{5x} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of (e^x+10)^{5x}

x \to 0 + lim ((e^{x} + 10)^{5 x})

1

Solution steps

x \to 0 + lim ((e^{x} + 10)^{5 x})

Plug in the value

x = 0

= (e^{0} + 10)^{5 \cdot 0}

Simplify

= 1

x \to 4 lim (2 x + 5)

x \to 4 lim (\frac{1}{16 - x ^{2}})

x \to \infty lim (\frac{x ^{\frac{3}{2}}}{( x + 1 ) ^{\frac{3}{2}}})

x \to 0 lim (sin (x) cot (2 x))

x \to 3 lim (x^{2} - 3 x + 7)

What is the limit as x approaches 0+of (e^x+10)^{5x} ?
The limit as x approaches 0+of (e^x+10)^{5x} is 1