What is the limit as x approaches-1/2 of-7/(2x+1) ?

The limit as x approaches-1/2 of-7/(2x+1) is diverges

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limit as x approaches-1/2 of-7/(2x+1)

x \to - \frac{1}{2} lim (- \frac{7}{2 x + 1})

diverges

Solution steps

x \to - \frac{1}{2} lim (- \frac{7}{2 x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - \frac{1}{2} + lim (- \frac{7}{2 x + 1}) = - \infty

x \to - \frac{1}{2} - lim (- \frac{7}{2 x + 1}) = \infty

= diverges

x \to - 2 lim (x^{2} - 3 x + 2)

x \to - 2 lim ((x^{2} - 4 x + 5)^{2})

x \to 0 + lim (ln (x) \cdot sin (x))

n \to \infty lim (\frac{n cos ( nπ )}{2 n - 1})

x \to 4 lim (\frac{x}{( x - 4 ) ^{2}})

What is the limit as x approaches-1/2 of-7/(2x+1) ?
The limit as x approaches-1/2 of-7/(2x+1) is diverges