What is (\partial)/(\partial t)(s^2+t^2) ?

The answer to (\partial)/(\partial t)(s^2+t^2) is 2t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial t)(s^2+t^2)

\frac{\partial}{\partial t} (s^{2} + t^{2})

2 t

Solution steps

\frac{\partial}{\partial t} (s^{2} + t^{2})

Treat

s

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (s^{2}) + \frac{\partial}{\partial t} (t^{2})

\frac{\partial}{\partial t} (s^{2}) = 0

\frac{\partial}{\partial t} (t^{2}) = 2 t

= 0 + 2 t

Simplify

= 2 t

\int \frac{x}{1 + x ^{2}} ln (1 + x^{2}) d x

\int \frac{x ^{2} + 1}{( x - 8 ) ( x - 7 ) ^{2}} d x

\int_{0}^{1} 5 (1 + x)^{7} d x

n = 1 \sum \infty n sin (\frac{3}{n})

\frac{d}{d x} (e^{x^{2} + c o s (x)})

What is (\partial)/(\partial t)(s^2+t^2) ?
The answer to (\partial)/(\partial t)(s^2+t^2) is 2t