limit as x approaches infinity of sqrt(16x^2+8x+6)-sqrt(16x^2+8x+6)

Solution

x \to \infty lim (16 x^{2} + 8 x + 6 - 16 x^{2} + 8 x + 6)

0

Solution steps

x \to \infty lim (16 x^{2} + 8 x + 6 - 16 x^{2} + 8 x + 6)

Simplify

= x \to \infty lim (0)

x \to a lim c = c

= 0

x \to - 2 + lim (\frac{x ^{2} - x}{x + 2})

x \to 0 lim ((1 - x) \frac{1}{x})

x \to 4 lim (\frac{1}{x})

x \to 0 lim (3 - 8 x + 3 x^{2})

x \to 1 - lim (\frac{- 2}{x - 1})

What is the limit as x approaches infinity of sqrt(16x^2+8x+6)-sqrt(16x^2+8x+6) ?
The limit as x approaches infinity of sqrt(16x^2+8x+6)-sqrt(16x^2+8x+6) is 0