What is (\partial)/(\partial x)(e^{-t}*cos(pix)) ?

The answer to (\partial)/(\partial x)(e^{-t}*cos(pix)) is -pie^{-t}sin(pix)

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(\partial)/(\partial x)(e^{-t}*cos(pix))

\frac{\partial}{\partial x} (e^{- t} \cdot cos (π x))

- π e^{- t} sin (π x)

Solution steps

\frac{\partial}{\partial x} (e^{- t} cos (π x))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- t} \frac{\partial}{\partial x} (cos (π x))

Apply the chain rule:

- sin (π x) \frac{\partial}{\partial x} (π x)

= - sin (π x) \frac{\partial}{\partial x} (π x)

\frac{\partial}{\partial x} (π x) = π

= e^{- t} (- sin (π x) π)

Simplify

= - π e^{- t} sin (π x)

\frac{2}{x - 8} (10.1)

\int r 1 - r^{2} d r

7 x^{2} - 3 x, x^{3} - 7 x + 2

x \to πk lim (sin (\frac{1}{x}))

y^{^{'}} - \frac{2}{x} y = 2 x^{- 1} y^{- 1}

What is (\partial)/(\partial x)(e^{-t}*cos(pix)) ?
The answer to (\partial)/(\partial x)(e^{-t}*cos(pix)) is -pie^{-t}sin(pix)