What is the limit as x approaches 1 of log_{2}(8x) ?

The limit as x approaches 1 of log_{2}(8x) is 3

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limit as x approaches 1 of log_{2}(8x)

x \to 1 lim (lo g_{2} (8 x))

3

Solution steps

x \to 1 lim (lo g_{2} (8 x))

Plug in the value

x = 1

= lo g_{2} (8 \cdot 1)

Simplify

lo g_{2} (8 \cdot 1) : 3

= 3

x \to \infty lim ((5 x)^{\frac{1}{x}})

x \to 0 lim ((x + sin (x))^{x})

x \to 0 lim (2 e^{x})

x \to - \infty lim (- 5 x)

x \to \infty lim ((2 x^{- 5} + 1)^{6 x^{5}})

What is the limit as x approaches 1 of log_{2}(8x) ?
The limit as x approaches 1 of log_{2}(8x) is 3