What is the derivative of (2x-1)e^x ?

The derivative of (2x-1)e^x is 2e^xx+e^x

What is the first derivative of (2x-1)e^x ?

The first derivative of (2x-1)e^x is 2e^xx+e^x

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derivative of

(2 x - 1) e^{x}

2 e^{x} x + e^{x}

Solution steps

\frac{d}{d x} ((2 x - 1) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x - 1, g = e^{x}

= \frac{d}{d x} (2 x - 1) e^{x} + \frac{d}{d x} (e^{x}) (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (e^{x}) = e^{x}

= 2 e^{x} + e^{x} (2 x - 1)

Simplify

2 e^{x} + e^{x} (2 x - 1) : 2 e^{x} x + e^{x}

= 2 e^{x} x + e^{x}

y = 3 x^{2} - 4 x + 1

sin (x), 5

\frac{( 16 s + 5 )}{( s ^{2} + 9 )}

\int_{- 2}^{3} 1

\int \frac{e ^{\frac{1}{x ^{2}}}}{x ^{3}} d x

What is the derivative of (2x-1)e^x ?
The derivative of (2x-1)e^x is 2e^xx+e^x
What is the first derivative of (2x-1)e^x ?
The first derivative of (2x-1)e^x is 2e^xx+e^x