What is the limit as x approaches 1 of (x-1)ln(x-1) ?

The limit as x approaches 1 of (x-1)ln(x-1) is Does not exist

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limit as x approaches 1 of (x-1)ln(x-1)

x \to 1 lim ((x - 1) ln (x - 1))

Does not exist

Solution steps

x \to 1 lim ((x - 1) ln (x - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim ((x - 1) ln (x - 1)) = 0

x \to 1 - lim ((x - 1) ln (x - 1)) =

Does not exist

= Does not exist

x \to \infty lim (x^{5 x})

x \to 9 lim (x^{2} + 4)

x \to 2 + lim (x + f (x) (x + 2))

x \to \infty lim (\frac{ln ( 2 + e ^{3 x} )}{ln ( 3 + e ^{2 x} )})

x \to 2 lim (x^{2} + 5 x - 3)

What is the limit as x approaches 1 of (x-1)ln(x-1) ?
The limit as x approaches 1 of (x-1)ln(x-1) is Does not exist